We @ www.denews.in bring before you all placement papers for selection conducted by Wipro Technologies in PDF downloadable format and also for your convenience in plain text format. Wipro Limited (Western India Products Limited) is an Indian multinational IT Consulting and System Integration services company headquartered in Bangalore, India.As of March 2015, the company has 158,217 employees servicing over 900 of the Fortune 1000 corporations with a presence in 67 countries. On 31 March 2015, its market capitalization was approximately $ 35 Billion, making it one of India's largest publicly traded companies and seventh largest IT Services firm in the World. To focus on core IT Business, it demerged its non-IT businesses into a separate company named Wipro Enterprises Limited with effect from 31 March 2013.The demerged companies are consumer care, lighting, healthcare and infrastructure engineering which contributed approximately 10% of the revenues of Wipro Limited in previous financial year.

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*WIPRO PLACEMENT PAPERS QUESTIONS WITH SOLUTIONS ALL IN ONE 8 SECTIONS*
1. 12 members were present at a
board meeting. Each member shake hands with all of the other members before and
after the meeting .How many hand shakes were there?

a) 130

b)134

c)132

d)135

Answer: C

Explanation:

In order to have a hand shake there must be two
members. Therefore to select 2 out of 12
we have 12C2.

This happens twice that is before and after the meeting

Answer = 12C2 ×2 = 132

2. An emergency vehicle travels 10
miles at a speed of 50 miles per hour.
How fast must the vehicle travel
on return trip if the round trip travel time is to be 20 minutes?

a) 75 mph

b) 70 mph

c) 65 mph

d) 80 mph

Answer: a

Explanation:

Going trip time = t = ds = 1050×60 = 12 minutes.

Given total time = 20 minutes

Return trip time = Total time – Going trip time = 20 – 12 =
8 minutes = 860 hours.

As the distance is 10 miles during even return trip,

The return speed = dt = 10860 = 10×608 = 75 mph

3. Mary and John can do a piece of
work in 24 day; John and Vino in 30 days;Vino and Mary in 40 days. If Mary,
John and Vino work together they will complete work in ?

a) 10 days

b) 20 days

c) 47 days

d) 45 days

Answer: b

Explanation:

Given that

Mary and John take 24 days; i.e., (Mary + John)'s 1 day's work
= 124

John and Vino take 30 days; i.e., (John + Vino)'s 1 day's
work = 130

Vino and Mary take 40 days; i.e., (Vino + Mary)'s 1 day's
work = 140

Adding above 3 equations, we get,

[(Mary + John) + (John + Vino) + (John + Vino)]'s 1 day's
work = 124+130+140

2((Mary + John + Vino)'s 1 days work = 124+130+140

2(Mary + John + Vino)'s 1 days work = 5+4+3120 = 110

Therefore, (Mary + John + Vino)'s 1 days work = 120

i.e., Mary, John and Vino together can complete the work in
20 days.

4. My friend collects antique
stamps. she purchased two, but found that she needed to raise money urgently.
So she sold them for Rs. 800 each. On one she made 20% and on the other she
lost 20%. How much did she gain or lose in the entire transaction?

a) she lost Rs 500.67

b) she lost Rs 666.67

c) she gain Rs 666.67

d) she gain Rs 500.67

Answer: b

Explanation:

Selling prices were given. Assume that on the first stamp
she made profit and on the second stamp she made loss.

So cost prices of the both stamps = 800120%+80080% = 1666.66

So She incurred a loss of 66.66 rupees.

5. If the sum of n terms of two
series in A.P. are in the ratio (5n + 4) : (9n + 6) then find the ratio of
their 13th terms.

a. 129231

b. 12

c. 2315

d. None of the above

Answer: a

Explanation:

Formula for sum of n terms in AP = Sn =
n2(2a + (n – 1)d ]

5n + 4 ⇒ 5(n – 1) +
9 ⇒ [2(92)+(n−1)5]

Common difference (d) = 5, First term (a) = 92

Similarly

Second series given 9n + 6 ⇒ 9(n – 1) +
15 ⇒ [2(152)+(n−1)9]

Common difference (d) = 9, First term (a) = 152

So

13th term for first series is = a + 12d = 1292

13th terms for second
series is = a + 12d = 2312

Ratio = 129231

6. A team P of 20 engineers can complete work or task in 32
days. Another team Q of 16 engineers can complete same task in 30 days.Then the
ratio of working capacity of 1 member of P to the 1 member of Q is

a. 3 : 2

b. 4 : 3

c. 2 : 5

d. 3 : 5

Answer: b

Explanation:

Let the capacity of an engineer in P = x units, and in Q = y
units.

Working capacity of P
= x × 32 × 20

Working capacity of Q = y × 16 × 30

As the total work is same, we equate the above equations.

⇒ x × 32 × 20 = y × 16 × 30

⇒ xy=16×3032×20=34

7. Ravi's salary was reduced by 25%. Percentage increase to be effected to bring
salary to original level =

a. 20%

b. 25%

c. 33 1/3 %

d. None of the above

Answer: b

Explanation:

Let the Salary be 100.

Salary was reduced by 25%.
So present salary = 75.

Percentage has to be increased in order to get Original
level = 2575×100 = 33.33 %

8. An ore contains 25% of an alloy that has 90% iron. Other
than this, in remaining 75% of the ore ,there is no iron. How many kgs of the
ore are needed to obtain 60 kg. of pure iron.?

a.250

b.275

c.300

d.166.66

Answer: d

Explanation:

Let us take 100x kgs of ore. Now it contains 25x kgs of
alloy and it contains 90% (25x) kgs of iron.

90% (25x) = 60 kg ⇒ x =
60×10090×125 = 83

So iron ore required = 100 × 83 = 266.66

9. Find the day of the week on 16th july, 1776.

a. Sunday

b. Monday

c. Tuesday

d. Wednesday

Answer: c

Explanation:

Split the year 1775 + 16th july 1776

Till 1600 years no odd days.

1601 to 1700 = 5 odd days

1701 to 1775 = 75 + 18 = 93 = 2 odd days. (75 years has 93 odd days (∵ 18 leap + 57 non leap years)

upto 15th july 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 =
197 = 1 odd day.

Total odd days = 5 + 2 + 1 = 8 = 1 odd day.

So one day after Monday. That is Tuesday.

10. The radius of a sphere is increased by 50%. The increase
in surface area of the sphere is :

a. 100%

b. 125%

c. 150%

d. 200%

Answer: b

Explanation:

Take radius 100. Then surface area is 4 × π × 100 × 100.

After increase radius by 50% the radius becomes100 + 50% of
100 = 150

Then new surface area is 4 ×
π × 150 × 150

Then put the values into formula of percentage =
4π1502−4π10024π1002×100 = 125%

11. On 8th Dec, 2007 Saturday falls. What day of the week
was it on 8th Dec, 2006?

A.Sunday

B.Thursday

C.Tuesday

D. Friday

Answer: d

Explanation:

8th Dec 2007 – 8th Dec 2006 = 52 weeks 1 day. So Dec 8th 2006 is behind one day = Friday

12. Which one of the following option is the closest in the
meaning to the word given below..

MITIGATE

a) Diminish

b) Divulge

c) Dedicate

d) Denote

Answer: a

Explanation:

Mitigate means to make something less severe. Divulge means reveal. Denote means indicate.
Diminish means to make or to cause something to become less in size, importance
etc.

13. On increasing the price of T.V. sets by 30%, their sale
decreases by 20%. What is the effect on the revenue receipts of the shop ?

a. 4% increase

b. 4% decrease

c. 8% increase

d. 8% decrease

Answer: a

Explanation:

Let the price be = Rs.100, and number of units sold = 100

Then, sale value = Rs.(100 × 100) = Rs.10000

New sale value = Rs.(130 × 80) = Rs.10400

Increase% = 40010000
× 100 = 4%

14. In an examination, 35% of total students failed in
Hindi, 45% failed in English and 20% in both. The percentage of these who
passed in both the subjects is :

a. 10%

b. 20%

c. 30%

d. 40%

Answer: d

Explanation:

Formula n(a∪b) = n(a) +
n(b) − n(a∩b)

Fail in Hindi or English = 35 + 45 – 20 = 60

Therefore students who passed = 100 – 60 = 40.

15. Find the angle between the minute hand and hour hand of
a click when the time is 7.20?

Answer: 100 degrees

Explanation:

Use formula θ=∣∣∣30h−112m∣∣∣

θ=∣∣∣30×7−112×20∣∣∣=1000

16. How will you measure height of building when you are at
the top of the building? And if you have stone with you.

Answer:

Explanation:

Throw stone from top and note the time,t.

Find height using formula

s = u × t + 0.5 × g ×
t2

Where u = 0

1.

1) B is mother of D but D is not daughter of B.

2) A is son of M and brother of G.

3) G is sister of D

Which of the following cannot be referred from the given
information ?

(A) B has 3 children

(B) M has two sons

(C) G is younger to B.

(D) A is younger to D

Answer: d

Explanation:

D is the son of B.
Also from the third clue, G and D are siblings. A is the brother of G
(from 2nd clue). So A, G, D are siblings. A is the son of M. So M is the father
(as B is the mother).

Finally, B and M has 3 children : 2 Sons D & A, and
daughter G.

Definitely G is younger to B as she is daughter of G

But it can't be said who is younger among children A,D &
G. So option D is not inferred.

2. A contractor undertook to make 15 km of roadway in 40
weeks. In 10 weeks, 3 km was complete by 180 men working 8 hours a day. The men
then agreed to work 1 hour a day overtime, And some boys were engaged to assist
them, the work was finished in the stipulated time(40 weeks). How many boys
were employed, if the work of 3 boys is equal to that of 2 men?

a) 70

b) 50

c) 60

d) 80

Answer: b

Explanation:

Let the capacity of man = 3 units, and boy = 2 units per
hour.

Now total work = 3×180×8×7×10 = 3 km. - - - - - - - (1)

Let k boys were recruited. Now total work = (3×180+2×k)
×9×7×30 = 12km. - - - - - - (2)

By dividing 2nd equation by 1st,

⇒ (540+2k)×9×7×303×180×8×7×10=4

⇒ k = 50

3. A can do a piece of work in 10 days, B in 15 days. They
work for 5 days. The rest of work finished by C in 2 days.If they get Rs 1500
for the whole work, the daily wages of B and C are?

Answer:

Explanation:

Let the total work = 30 units.

Then capacity of A = 3 units, B = 2 units. Now they worked
for 5 days. So they must have completed 25 units. Rest of the work 5 units done
by C in 2 days. So C capacity = 5/2 = 2.5 units.

Given that toatal wages are Rs.1500 for 30 units. So for 1
unit of work they get Rs.50. Now B and C per day work = (2 + 2.5) = 4.5 units.
So their daily wages = 4.5 × 50 = Rs.225

4. The average of ten numbers is 7 .If each number is
multiplied by 12 , then the average of new set of numbers is :

a) 7

b) 19

c) 82

d) 84

Answer: d

Explanation:

If each number is multiplied by K, then the new average
increases by K times. So new average =
84

5. In an examination, a student scores 4 marks for every
correct answer and loses 1 mark for every wrong answer. If he attempts all 75
questions and secures 125 marks, the number of questions he attempts correctly,
is :

a) 35

b) 40

c) 42

d) 46

Answer: B

Explanation:

Let the number of correct answers be x.

Then numbers of incorrect answers will be 75 – x

We get 4x – (75 – x)×1= 125

On solving the equation we get x= 40

6. A car moves at the speed of 80 km/hr. what is the speed
of the car in metres per second?

A. 8 m/sec

B. 20 × 19 m/sec

C. 21 × 29 m/sec

D. 22 × 29 m/sec

Answer: D

Explanation:Formula

For convert km/hr into m/sec multiply the speed with 518

For convert m/sec into km/hr multiply the speed with 185

80 × 518 ⇒ 22 × 29 m.sec.

7. 3 men can complete a piece of work in 6 days. Two days
after they started the work, 3 more men joined them. How many days will they
take to complete the remaining work?

Answer: 2 days

Explanation:

3 man 1 day work = 16

3 man 2 days work =
26

Remaining work = (1 –
26 ) = 2/3 parts.

6 man together perform the work in 1 day is = 16 + 16 = 26 parts

26 parts completed in 1 day

23 parts will b completed in
2 days

8. A single discount % equal to three successive discounts
of 30%, 20% and 10%.

A. 49.6%

B. 50.4%

C. 40%

D. 60%

E. None of these

Answer: a

Explanation:

Let the initial price be 100.

30% discount on 100 is 30

(100 – 30) = 70

20% discount on the 70 is 14

(70 – 14) = 56

10%discount on the 56 is 5.6

So the answer is 30 + 14 + 5.6 = 49.6

9. If "PROMPT" is coded as QSPLOS ,then
"PLAYER" should be

(a) QMBZFS

(b) QMBZDW

(c) QUREXM

(d) QMBXDQ

Answer: d

Explanation:

1st 3 letters are denoted by its next alphabet and the next
3 letters are denoted by its previous alphabets.

10.Which of the following are phases of 2-phase locking
protocol?

1) Intent to request locks

2) Release the present locks and never asking for
transmission

3) Both (1) and (2)

4) None of these

Answer: 3

11.When an array of pointers is passed through a function,
what actually is passed?

1) address of the starting element

2) last element

3) first element

4) number of elements

Answer: 1

Explanation:

When any array is passed through a function,always the
address of starting element is passed

12. If the operation,^ is defined by the equation x ^ y = 2x
+ y, what is the value of a

in 2 ^ a = a ^ 3

A)-2

B)-1

C)0

D)1

Answer: d

Explanation:

2^a = 2 × 2 + a - - -
(i)

a^3 = 2 × a + 3 - - - (ii)

4 + a = 2a + 3

⇒ a = 1

13. In a certain school, 20% of the students are below 8 yrs
of age. The number of students above 8 yrs of age is (2/3) of the number of
students of 8 years age which is 96. What is the total number of students in
the school?

Answer: 200

Explanation:

Let total students be x.

⇒ 0.2x + 23 × 96 + 96 = x

⇒ x = 200

14. If there are 5,000 voters out of which 20% are not
eligible to vote and there are two candidates contesting. The winning candidate
won by 15% of votes. What is the total number of votes he got ?

Answer: 2300

Explanation:

Number of voters eligible for voting = 5000 × 0.8 = 4000

Number of votes extra got by the winning candidate = 4000 × 0.15 = 600

Let the number of votes won by winning candidate = x.

⇒ x – (4000 – x) = 600

⇒ x = 2300

15. Find the set of all points (x, y) such that the area of
the triangle with vertices (0, 0), (6, 4) and (x, y) is 4.

A).(x, y) lies on the circle (y – 6)2 + (x – 4)2 = 16

B).(x, y) satisfies 6y – 4x = 8 or 6y – 4x = –8

C).(x, y) satisfies 6y – 4x = 4 or 6y – 4x = –4

D).(x, y) satisfies 6y – 4x = 8

Answer: b

Explanation:

Area of a triangle if one of the point is (0, 0) =
12|(x1y2−x2y1)|

⇒ 12|(6×y−4×x)| = 4

⇒ 6y – 4x = 8

16. When not moving on the sidewalk, Maya can walk the
length of the sidewalk in 7 minutes. If she stands on the sidewalk as it moves,
she can travel the length in 4 minutes. If Maya walks on the sidewalk as it
moves, how many minutes will it take her to travel the same distance? Assume
she always walks at the same speed, and express your answer as a decimal to the
nearest tenth.

(a) 3.6

(b) 2.5

(c) 3.8

(d) 2.8

Answer: b

Explanation:

Assume distance of sidewalk "x"

Speed 1 (moving on sidewalk)

Speed 2 (moving off sidewalk)

Since both the movements are in same direction, we can do
speed 1 + speed 2

Speed 1 = x4

Speed 2 = x7

Speed 1 + speed 2 = 11x28 =
= 0.39286x

Now new time while moving on sidewalk = x0.39286x = 2.54544

Hence, the answer is 2.5

17. The ages of Old and Young total 48. Old is twice as old as Young was when Old was
half as old as Young will be when Young is three times as Old was when Old was three
times as old as Young. How old is Old?

(a) Old-42, Young-26

(b) Old-38, Young-22

(c) Old-30, Young-18

(d) Old-28, Young-14

Answer: c

Explanation:

From the options itself,we can see that option c

old = 30

young = 18

30 + 18 = 48

By reducing this years only by one

Before 6years

old = 24 (half of young)

young = 12 (twice of old)

1. Mr.P and Mr.Q can build a wall in 10 days; Mr.Q &
Mr.R can take 14 days to build the same wall; and Mr.P and Mr.R can do it in 8
days. Who among them will take more time when they work alone?

a. p

b. q

c. r

d. data inadequate

Answer: b

Explanation:

Let the total work be 280 units.

Now P and Q capacity per day = 280/10 = 28 units.

Q and R capacity per day =280/14 = 20 units

P and R capacity per day = 280/8 = 25 units.

Adding all the three,

2(P + Q + R) = 73 ⇒ P + Q + R
= 36.5 units.

We are asked to find who will take maximum time. So the
capacity is minimum. R capacity is
minimum as (P + Q + R) - (P + R) = 36.5 - 28 = 8.5.

2. Each week the forensics teams at Roslyn High School and
Manchester High School debate each other. Each team has several members, and
each week three are selected to debate. Whenever Aviva debates for Roslyn,
Roslyn wins; and whenever Zachary debates for Roslyn, Roslyn wins. Whenever
Josh debates for Roslyn, Manchester wins.

If one week Roslyn lost to Manchester, which of the
following must be true?

(a) Josh debated for Roslyn.

(b) Either Aviva or Zachary debated for Roslyn.

(c) Neither Aviva nor Zachary debated for Roslyn.

(d) Josh and either Aviva or Zachary debated for Roslyn.

Answer: A

Explanation:

It is clear that if Josh debates for Rosln, Manchester wins.
So Option A is correct.

3. In a class of boys and girls Vikas's rank is 9th and
Tanvi's rank is 17th . Vikas's rank among the boys in that class is 4th from
the top and 18th from the bottom and Tanvi's rank among the girls is 8th from
top and 21st from bottom. In the order of rank, how many girls are there
between Tanvi and Vikas?

A) 1

B) 2

C) 5

D) 3

Answer: b

Explanation:

Vikas's rank in the class is 9. So there are 8 people before
him. His rank among boys is 4. So 3 boys
are before him. So there are 8 – 3 = 5
girls before him.

Tanvi's rank among the girls is 8. So there are 7 girls before her. So number of girls between Vikas and Tanvi is
7 – 5 = 2

4. Two Equal Amounts of Money are lent out at 6% and 5 %
simple Interest respectively at the same time. The former is recovered two
years earlier than the latter and the amount so recovered in each case is
Rs.2800. Determine the amount that is lent out?

A) 1950

B) 1500

C) 1800

D) 1375

Answer:

Explanation:

Let the first amount lent for t + 2 years and second at t
years. and amount = P

Now amount = P + P×t×6100 = P×(t+2)×5100 = 2800.

Equating first two parts, we get t×6100=(t+2)×5100

⇒ t = 10.

Now P+P×10×6100=2800

⇒ 1610P=2800

⇒ P = 1750.

5. A starts business with Rs.3500 and after 5 months, B
joins with A as his partner. After a year, the profit is divided in the ratio 2
: 3. What is B’s contribution in the Capital ?

Answer: 9000

Explanation:

A invested Rs.3500 for 12 months.

Let B joined with investment x. And he invested for 12 - 5 = 7 months.

So there profit ratio = (3500 × 12) : (7x) = 2 : 3

⇒ x
= 9000

6. Rajan and Rakesh started a business and invested Rs.20000
and Rs.25000 respectively. After 4 months Rakesh left and Mukesh joined by
investing Rs.15000. At the end of the year there was a profit of Rs.4600. What
is the share of Mukesh?

A). Rs.1500

B). Rs.1400

C). Rs.1300

D). Rs.1200

Answer: d

Explanation:

Rajan is in the business for 12 months, Rakesh is for 4, and
Mukesh is for 8.

Profits will be divided in ratio of (20 × 12) : (25 × 4) :
(15 × 8) = 24 : 10 : 12

Share of Mukesh = 1246×4600=1200

7. Plastic strap are wound around large cardboard boxes to
reinforce them during shipping. Suppose the end of the strap must overlap 7/16
inch to fasten. How long is the plastic strap around the box of dimensions 28
5/16 inch × 24 9/16 inch

A). 106 3/16

B). 96 3/16

C). 105 3/16

D). 107 3/16

Answer: a

Explanation:

Strap should cover two walls of the given parameter.

2 × (28 5/16 inch + 24 9/16 inch) + 7/16 = 106 3/16 inch

8. In a game each person is dealt three cards from a deck of
52 cards and a player is said to have a winning deck if & only if he or she
has a king, queen & a jack each , irrespective of the color of the sign.
What is the total possible number of winning decks for this game?

(a)1

(b)4

(c)16

(d)64

(e)128

Answer: d

Explanation:

Here king can be selected in 4C1 ways

And other is queen & jack are also selected in the same
way.

So 4C1 × 4C1 × 4C1 = 4 × 4 × 4 = 64

9. In a group of cows and hens, the number of legs are 14
more than twice the number of heads. The number of cows is :

a. 5

b. 7

c. 10

d. 12

Answer: b

Explanation:

Let the number of cows be x and hens be y.

So heads = x + y

Legs = 4x + 2y

Now

⇒ 4x + 2y = 2(x + y) + 14

⇒2x = 14

⇒ x = 7.

10.

1 = 5

2 = 10

3 = 15

4 = 20

5 = ?

Answer: 1

Explanation:

Check the question clearly.

Answer is "1" as 1 = 5

Then 5 should be 1.

11. If six persons sit around a table, the probability that
some specified three of them are always together is

a)1/20

b)3/10

c)1/5

d)4/5

Answer: b

Explanation:

Let us group those 3 persons into one. Now 4 elements can be
arranged in a circle in (4 - 1)! ways. Now those three persons in that group
can arrange themselves in 3! ways. So total ways = 3! × 3!.

Total ways of arranging 6 persons around a circle = (6-1)!.

Probability = 3!×3!5!
= 310

12. Out of four numbers ,the average of first three is 16
and that of the last three is 15 .If the last number is 18,the first number is
:

A) 20

B) 21

C) 23

D) 25

Answer: b

Explanation:

Let the numbers be a, b, c, d

From the 1st condition, Sum of the first three numbers
= a + b + c = 16 × 3 = 48

In the 2nd condition, b + c + d = 45

Now,d is given value as 18

thus, b + c + 18 = 45

b + c = 27

Putting the value of b + c in equation, a + b + c = 48

⇒ a + 27 = 48

⇒ a = 21

13. Mr. X has to build a wall 1000 meters long in 50 days.
He employs 56 men but at the end of 27 days finds that only 448 meters are
built. How many more men must be employed so that the work may be finished in
time?

a)58

b)81

c)38

d)25

Answer: d

Explanation:

Initially Mr.X over estimated the capacity of the workers.
Infact, 56 men built 448 meters in 27 days.
So our problem is to find How many men can built 552 meters in 23 days.
Use chain rule.

Required number of men = 56×552448×2723 = 81

Additional number of men = 81 – 56 = 25

14. In a race you drove 1st lap with 40 kmph and in the
second lap at what speed you must drive so that your average speed must be 80
kmph.

Answer: Infinity

Explanation:

Infinite speed.

Let distance of lap be d km.

Total distance = 2d km.

Time for first lap = d/40 kmph and that for second lap = d/x
kmph, where x is requied speed.

Average speed = (total distance)/ (total time)

⇒ 2d/(d/40+d/x)

⇒ 2/(1/40+1/x).

Given this is equal to 80.

So, 2/(1/40+1/x) = 80

2 = 2 + 80/x.

Which means 80/x = 0.

For that x must be equal to infinity.

15. A and B working separately can do a piece of work in 6
and 9 days respectively; they work on alternate days starting with A on the
first day. In how many days will the work be done?

Answer: 7

Explanation:

A = 1/6 days

B = 1/9 days

With A starting the work

In a period of 2 days work done by a and b = 1/6 + 1/9 =
5/18

In 3 such periods work done
= 5/18 + 5/18 +5/18 = 15/18

Remaining work = 1 – 15/18 = 1/6

Now its a turns and it can complete the remaining work

So number of days = 3 × 2 + 1 = 7

16. In a certain office, 72% of the workers prefer tea and
44% prefer coffee. If each of them prefers tea or coffee and 40 like both, the
total number of workers in the office is :

a. 200

b. 240

c. 250

d. 320

Answer: c

Explanation:

If the total number of workers is 100 then 72 prefer tea and
44 prefer coffee.

n(Tea ∪ Coffee) =
n(Tea) + n(Coffee) - n(Tea ∩ Coffee)

100 = 72 + 44 – x

x = 116 – 100 = 16.

Therefore Out of 100 workers, 16 take both coffee and tea.

But as per the problem 40 take both coffee and tea

100 - - - 16

? - - - - - 40

(40/16) × 100 = 250.

17. P & Q can draw a picture in 144 hours; Q & R can
draw a same picture in 240 hours; P & R can finish it in 180 hours. What
will be the time taken by P alone to draw the picture?

a) 280 hours

b) 240 hours

c) 200 hours

d) 300 hours

Answer: b

Explanation:

Given that, (P + Q) takes 144 hours; i.e., (P + Q)'s 1
hour's work = 1144

(Q + R) takes 240 hours; i.e., (Q + R)'s 1 hour's work
= 1240

(P + R) takes 180 hours; i.e., (P + R)'s 1 hour's work
= 1180

Adding above 3, we get,

2(P + Q + R)'s 1 hour's work = 1144+1240+1180 = 5+3+4720= 12720 = 160

2(P+Q+R)'s 1 hour's work = 160

Therefore, (P+Q+R)'s 1 hour's work = 1120

Now, P's 1 hour's work = (P+Q+R)'s 1 hour's work - (Q+R)'s 1
hour's work

= 1120 - 1240 = 1240

Therefore P alone takes 240 hours.

1. A 10 Liter mixture of milk and water contains 30 percent
water. Two liters of this mixture is taken away. How many liters of water should now be added
so that the amount of milk in the mixture is double that of water?

(a) 1.4

(b) 0.8

(c) 0.4

(d) 0.7

Answer: c

Explanation:

Two liters were taken away So we have only 8 liters of
mixture.

Amount of milk in 8 liters of mixture = 8 × 70% = 5.6 liters

Amount of water in 8 lit of mix = 8 - 5.6 = 2.4 liters.

Half of milk i.e half of 5.6 = 2.8 liters.

We need (2.8 - 2.4) liters water more = 0.4 lit

2. A frog can climb up a well at 3 ft per min but due to
slipperiness of the well, frog slips down 2 ft before it starts climbing the
next minute. If the depth of the well is 57 ft, how much time will the frog
take to reach the top?

Answer: 55 min

Explanation:

As per given, in 1 min,frog climbs up 3 ft and slips down by
2 ft.

So the frog climbs only 1 ft in 1 min

So after 54 mins,it would have climbed 54ft.

At the end of 55 mins it climbs up 3 ft to make it 57 ft and
come out of the well.

Once it had reached the destination,it will not slip.

So the frog will take only 55 minutes to climb up the well.

3. A rectangle has twice the area of a square. The length of
the rectangle is 14 cm greater than that side of the square whereas breadth is
equal to side of the square. Find the perimeter of the square?

(a) 42 cm

(b) 14 cm

(c) 56 cm

(d) 28 cm

Answer: c

Explanation:

Let side of square be x.

Then for rectangle length = 14 + x and breadth = x.

It is given

Area of rectangle = 2 × (area of square)

length × breadth = 2(x × x)

(x + 14) × x = 2 × x2

x2 + 14x = 2x2

x2 = 14x

x = 14.

Perimeter of square = 4 × x = 56

4. A man can row a distance of 5 km in 60 min with the help
of the tide. The direction of the tide reverses with the same speed. Now he
travels a further 20 km in 10 hours. How much time he would have saved if the
direction of tide has not changed?

(a) 5 hrs

(b) 4 hrs

(c) 12 hrs

(d) 6 hrs

Answer: d

Explanation:

He covered 5 km in 1 hour , so he might cover 20 km in 4
hours.

But he took 10 hours.

He would have saved 10 – 4 = 6 hours.

5.If half of 5 were 3, that would one-third of 10 be

(a) 5

(b) 4

(c) 3

(d) 2

Answer: b

Explanation:

Half of 5 is 2.5. But
given as 3. So take 1/2 of 5x = 3 ⇒ x = 6/5

Now 1/3 (10x) = 1/3 × 10 × 6/5 = 4.

6. A butler is promised Rs. 100 and a cloak as his wages for
a year. After 7 months he leaves this service, and receives the cloak and Rs.20
as his due. How much is the cloak worth?

(a) 76

(b) 84

(c) 92

(d) 68

Answer: c

Explanation:

Let be the price of cloak is = x

According to the Question he should get 7/12th of 100 and
7/12th of cloak.

712(100)+712(x)=20+x

⇒ x = 92.

7. A worm is at the bottom of a forty foot hole. It can
crawl upwards at the rate of four feet in one day, but at night, it slips back
three feet. At this rate, how long will it take the worm to crawl out of the
hole?

(a) 29 days

(b) 37 days

(c) 35 days

(d) 39 days

Answer: c

Explanation:

For each day worm climb only 4 - 3 = 1feet.

After 36 days worm reach the 36 foot.

Exactly the 37th day worm reach 40 foot and won't slips
back.

8. Sohan purchased a horse for Rs.2000 and sold it to Mohan
at a loss of 10 percent. Mohan sold it to Sham at a loss of 10 percent while
sham sold it to Gopi at a gain of 10 percent. The amount Gopi paid for it would
be

Answer: 1782

Explanation:

Cost price = 2000

Selling price = 90% (2000) = 1800.

Mohan sold this to Sham at a loss of 10%. So selling price =
90% (1800) = 1620

Sham sold this at 10% profit. So selling price = 110% (1620)
= 1782

9. On a map the distance between two mountains is 312
inches. The actual distance between the mountains is 136 km. Ram is camped at a
location that on the map is 34 inch from the base of the mountain. How many km
is he from the base of the mountain?

Answer: 14.82 km

Explanation:

Since 312 inch = 136 km

So 1 inch = 136/312 km

So 34 inch = (136 × 34)/ 312 = 14.82 km

10. Sixteen men complete a work in 24 days while 48 children
can do it in 16 days. Twelve men started the work, after 14 days 12 children
joined them. In how Many days will all of them together complete the remaining
work?

Answer: 12 days

Explanation:

Let man capacity = 2 units/day. Then total work = 16 × 2 × 24 = 768

Let the children capacity is k units/ days. So total work =
48 × k × 16

Equating above two equations we get k = 1. So children capacity = 1 unit / day.

Twelve men did 14 days of job. So they completed 12 × 2 ×14
= 336.

Remaining work = 768 - 336 = 432.

Now 12 children joined them. So per day capacity of entire
team = 12 × 2 + 12 × 1 = 36.

So they complete the remaining work in 432/36 = 12 days.

11. A father's age was 5 times his son's age 5 years ago and
will be 3 times son's age after 2 years, the ratio of their present ages is
equal to:

a) 3:7

b) 5:11

c) 10:3

d) 10:7

Answer: c

Explanation:

Let the Father's age = x, and Son's = y

x - 5 = 5(y – 5)

x + 2 = 3(y + 2)

Solving we get x/y = 10/3

12. At a reception, one-third of the guests departed at a
certain time. Later two-fifths of the guests departed. Even later two-thirds of
the remaining guests departed. If six people were left, how many were
originally present at the party?

Answer: c

Explanation:

Let Original members be x

First One third guest departed i.e x/3

Remaining guests = x
– (x/3) = 2x/3

Now from the remaining (2x/3) two-fifths departed =
2/5(2x/3) = 4x/15

i.e. Now remaining guests will be (2x/3 – 4x/15) = 2x/5

Now from remaining (2x/5) two-thirds departed = 2/3(2x/5) = 4x/15

Now remaining guests =
(2x/5 – 4x/15) = 2x/15

Given 2x/15 = 6 ⇒ x = 45

13. Ratio between 2 numbers is 5 : 7 and their product is
560.what is the difference between 2 numbers?

Answer: c

Explanation:

x/y = 5/7

x × y = 560 ⇒ x = 560/y

Substituting this value in first equation, we get 560/yy=57 ⇒560y2=57 ⇒ y = 28

x = 20

So difference between the numbers could be

x – y = –8

y – x = 8

14. A is 6 times as fast as B and takes 100 days less to
complete a work than B. Find the total number of days taken by A and B to
complete the work.

Answer: 120/7 days

Explanation:-

According to question A is 6 times as fast as B

So, Ratio of time taken by A and B will be 1 : 6

Let time taken by A is =
x

And time taken by B is = 6x

According to the question A take 100 days less

i.e. 6x – x = 100

x = 20

So, A takes 20 days and B takes 120 days to complete the
work.

A's 1 day work = 1/20

B's 1 day work = 1/120

(A + B)'s 1 day work = 1/20 + 1/120 = 7/120

Total time taken = 120/7 days.

15. 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges,
2 bananas and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and
3 apples

Answer: 15

Explanation:

2 O + 3 B + 4 A = 15 - - - - (1)

3 O + 2 B + 1 A = 10 - - - - (2)

Where A,B and O are number of apple, bananas, and oranges
respectively.

Adding 1 and 2,

5 O + 5 B + 5 A = 25 ⇒ 1 O + 1 A
+ 1 B = 5

now,

3O + 3A + 3B = 5 × 3 = 15

16. What is the next number of the following sequence

123, 444, 888, 1776, 8547, . . . . . .

Answer: 16005

Explanation:

1) 123 + 321 = 444

2) 444 + 444 = 888

3) 888 + 888 = 1776

4) 1776 + 6771 = 8547

5) 8547 + 7458 = 16005

17. Gavaskar average in first 50 innings was 50. After the
51st innings his average was 51. How many runs he made in the 51st innings

Answer: 101

Explanation:

Gavaskar average 50 in 50 innings so, total runs scored by
him = 50 × 50 = 2500.

Now after 51st innings, his total runs = Average is, 51 × 51
= 2601.

So runs scored in 51st innings = 2601 – 2500 = 101 runs

18. There are 30 socks in a drawer. 60% of the socks are red
and the rest are blue. What is the minimum number of socks that must be taken
from the drawer without looking in order to be certain that atleast two blue
socks have been chosen?

Answer: 20

Explanation:

Number of red socks = 30 × 60% = 18

If you draw out 18 socks there's a possibility that all of
them are red

If you draw out 19 socks one of them has to be a blue one

And if u draw 20 socks then definitely 2 of them are blue
socks

So the answer is 20.

1. 30 men take 20 days to complete a job working 9 hours a
day. how many hour a day should 40 men work to complete the job?

a. 8 hrs

b. 7 1/2 hrs

c. 7 rs

d. 9 hrs

Answer: 6.75

Explanation:

Let the capacity of man in hour is 1 unit. Then total work =
30 × 20 × 9

40 men in 20 days working t hours a day can complete = 40 ×
20 × t

⇒ 40 × 20 × t = 30 × 20 × 9

⇒ t = 6.75 hours.

2. If radius of a circle is diminished by 10% then its area
is diminished by

a) 10%

b) 19%

c) 20%

d) 36%

Answer: b

Explanation:

Let old radius = 10 units.

New radius is diminshed by 10%. So new radius = 90% (10) = 9
units.

Old area = π × r2 = 100π

New area = π × 92 = 81π

Change = 19π/100π
×100 = 19%

Alternatively:

For any two dimensional diagram the percentage change is
calculated by the formula: (a+b+ab100)%

Substitute a = -10, b = -10.

3. The ratio between speed of the two trains is 7:8. If the
2nd train runs 400 km in 4 hrs, what is the speed of the 1st train?

a) 85 kmph

b) 87.5 kmph

c) 90 kmph

d) 92.5 kmph

Answer: b

Explanation:

Speed of 2nd train = 400/4 = 100 kmph

Since the ratios are in 7 : 8

Speed of First train = 7/8 × 100 = 87.5 kmph

4. A car travelling 5/7th of its actual speed covers 42 km
in 1 hr 40 min 48 sec. what is the actual speed of the car?

a) 30 kph

b) 35 kph

c) 25 kph

d) 40 kph

Answer: b

Explanation:

Let the Actual Speed = x

It is travelling with 5/7 of its actual speed = 5x/7.

Converting the time into seconds = 3600 + 2400 + 48 seconds.

Covers a distance with speed = 42/(3600 + 2400 + 48)

= 424048 × 3600 = 25 kph

Given 5x7 = 25 kph

So Actual Speed = 25 × (7/5) = 35 kph

5. The ratio of the present ages of Sunita and Vinita is
4:5. Six years hence the ratio of their ages will be 14:17. What will be the
ratio of their ages 12 years hence?

1) 15:19

2) 13:15

3) 16:19

4) 17:19

5) None of these

Answer: 3

Explanation:

Present age sunita : vinita = 4 : 5

Let their age is 4x and 5x respectively..

After 6 yrs their age ratio will be 14 : 17

Therefore 4x+65x+6=1417

⇒ x = 9

Therefore their present ages are 36,45 respectively.

After 12 yrs their ages will be 48, 57 respectively.

⇒ Ratio after 12 years will be 48: 57 =
16: 19 = 16 : 19

6. If the price of petrol increases by 25% and Kevin intends
to spend only 15% more on petrol. By how much percent should he reduces the
quantity of petrol that he buys?

Answer: 8%

Explanation:

Let Petrol Price 100 per Liter and Quantity he purchases
equals to 100 Liters

Then total expenditure = 100 × 100 = 10000

Petrol Price is increased by 25%. So new price = 125 per litre

And he increases the expenditure by 15%. So expenditure limit = 11500

Now his quantity = 11500/125 = 92 liters

So the quantity is reduced by 8%

7. What is it answer?& it is a letter.

01100101

10000011

01110010

01111001

01110101.

Answer:

Explanation:

It is ASHOK as 01100101 10000011 01110010 01111001 01110101

65 83 72 79 75

A S H O K

8. If the circumference of a circle is 200 units, Then what
will the length of the arc described by an angle of 20 degree ?

Answer: 11.11

Explanation:

The angle formed by a circle is 360 degrees.

Length of the arc = θ360 × Circumference of the circle.

So Length of the arc = 20360×200

So, the length of the arc described by 20 degree angle is
11.11 units.

9. The average age of a class of 39 students is 15 years. If
the age of the teacher be included, then the average increases by 3 months.
Find the age of the teacher.

Answer: 25 y

Explanation:

Average age of 39 students = 15 yrs

Total age of 39 students = 39 × 15 = 585 yrs

Avg age of 39 students + teacher =15+ (3/12) =15.25 years

So the total age of (39 student + 1 teacher) or 40 persons =
40 × 15.25 = 610 years

So age of teacher = 610 – 585 = 25 years

10. A train leaves New York City at 7.15 Am and arrives in
Buffalo at 2.47 that afternoon. What total length of time does the trip take?

Answer: 7 h 32 min.

Explanation:

2.47 PM = 14.47

Total time = 14.47 – 7.15 = 7 hrs 32 min

11. In a row of boys Anand is eleventh from the left and
Deepak is fifteenth from the right. When Anand and Deepak interchange their
positions, Anand will be fifteenth from the left, which of the following will
be Deepak's position from the right?

Answer: 19

Explanation:

Anand is 11th from left and Deepak is 15th from right side

10 boys - Anand - x boys - Deepak - 14 boys.

After changing the position Anand's position is 15th from
left. (Put Anand in Deepak position). So x is 3. Now Deepak position from the
right is 14 + 1 + 3 + 1 = 19th.

12. A transport company's vans each carry a maximum load of
13 tonnes. 12 sealed boxes each weighing 9 tonnes have to be transported to a
factory. The number of van loads needed to do this is

option

a) 11

b) 12

c) 8

d) 9

Answer: b

Explanation:

12 as all boxes are sealed.

13. Maria drove to the mountains last weekend. There was
heavy traffic on the way there, and the trip took 9 hours. When Maria drove
home, there was no traffic and the trip only took 4 hours. If her average rate
was 40 miles per hour faster on the trip home, how far away does Maria live
from the mountains?

Answer: 288 miles

Explanation:

Time taken for trip from home to mountains = 9 h

Time taken for trip from mountains to home = 4 h

Let distance from home to mountains = x miles

let avg speed from home to mountains = y miles/h

Given avg speed on the trip home is 40 m/h faster than speed
from home to mountains = y + 40 m/h

⇒ (x/9) = y and (x/4) = y + 40

by solving this, we get y = 32 m/h and the distance x=32 × 9
= 288 miles.

14. If N = 23×34 , M = 22×3×5, then find the number of
factors of N that are common with the factors of M.

a. 20

b. 18

c. 6

d. 8

Answer: c

Explanation:

N = 23×34

M = 22×3×5

By taking common powers we get 22×3

So common factors = (2 + 1)(1 + 1) = 6.

(formula for number of factors of a number)

15. Susan can type 10 pages in 5 minutes. Mary can type 5
pages in 10 minutes. Working together, how many pages can they type in 30
minutes?

A. 15

B. 20

C. 25

D. 65

E. 75

Answer: E

Explanation:

Susan can type 2 pages in 1 min

Mary can type 0.5 pages in 1 min

so, both of them work together they type 2.5 pages in 1 min

so,in 30 min they type (30 × 2.5) = 75 pages

16. a and b are two numbers selected randomly from 1,2,3....
25 what is the probability of a and b are not equal.

(a) 1/25

(b) 24/25

(c) 13/25

(d) 2/25

Answer: b

Explanation:

Total outcomes = 25 × 25 = 625

Probability of getting a and b are equal= 25 [ ∴ (1,1),(2,2),(3,3).....(25,25)]

Probability of a and b or not equal = 1−25625 = 600625 =
2425

17. Worker W produces n units in 5 hours. Workers V and W
work independently but at the same time, produce n units in 2 hours. How long
would it take V alone to produce n units?

Answer: 10/3 h

Explanation:

w's 1 hours production = n/5

(w + v)'s 1 hours production = n/2

v's 1 hour production = n/5 + V = n/2

v's 1 hour production = n/2 – n/5 = 3n/10= n/(10/3)

Ans = 10/3 hours

18. If A speaks the truth 80% of the times, B speaks the
truth 60% of the times. What is the probability that they tell the truth at the
same time

(a) 0.8

(b) 0.48

(c) 0.6

(d) 0.14

Answer: b

Explanation:

Probability that A speaks truth is 80/100 = 0.8

Probability that B speaks truth is 60/100 = 0.6

Since both A and B are independent of each other

So probability of A intersection B is P(A) × P(B) =0.8 × 0.6
= 0.48

19. Carrey rented a car for Rs.20 plus Rs.0.25 per kilometer
driven. Samuel rented a car for Rs.24 plus Rs.0.16 per kilometer driven. If
each drove d km. and each was charged exactly the same amount for the rental,
then d equals ?

(a) 44.4

(b) 34.4

(c) 49.4

(d) 54.4

Answer: a

Explanation:

20 + 0.25 × d = 24 + 0.16d

Solving we get d = 44.4

1. If the day that will dawn 2 days after tomorrow is
Friday, what day of the week dawned two days before yesterday?

a. Wednesday

b. Friday

c. Thursday

d. Sunday

Sol:

Two days before Friday = Wednesday. So today is Tuesday.
Yesterday is Monday. Two days before monday = Saturday.

2. What should come in place of the question-mark (?) in the
following number series?

5690, 5121, 4552, 3983, 3414, 2845, ?

a. 2276

b. 2516

c. 2746

d. 2356

e. None of these

Sol:

The difference of the numbers in the series is same i.e 569.

5690 – 5121 = 569

5121 – 4552 = 569

4552 – 3983 = 569

3983 – 3414 = 569

3414 – 2845 = 569

So

2845 – 2276 = 569

3. A student scores 55% marks in 8 papers of 100 marks each.
He scores 15% of his total marks in English. How much does he score in English?

1) 55

2) 66

3) 77

4) 44

5) None of these

Sol. Given student scores 55% marks in english in 8 papers
of 100 marks each.

So,his total marks =
55/100 × 800 ⇒ 440

15% of his 440 marks is 440 × (15/100) ⇒ 66

So, he scored 66 marks in english.

Ans is option-2.

4. A person travels 12 km in the southward direction and
then travels 5km to the right and then travels 15 km toward the right and
finally travels 5km towards the east, how far is he from his starting place?

(a) 5.5 kms

(b) 3 km

(c) 13 km

(d) 6.4 km

Sol:

To solve these type of questions, first draw the direction
diagram and assume the person is at the intersection point.

From the diagram it is clear that he is 3 km from where he
started.

5. A person travels 6km towards west, then travels 5km
towards north ,then finally travels

6km towards west. Where is he with respect to his starting
position?

(a) 13km east

(b) 13km northeast

(c) 13km northwest

(d) 13km west

Sol:

From the above diagram it is he started at C and reached
position C. now ACD is a right angle triangle. AC = CD2+AD2−−−−−−−−−−√ =
52+122−−−−−−−√=13

So he is 13 km away from the starting position and in north
west position.

6. The difference between the compound and simple interest
on a certain sum for 2 years at the rate of 8% per annum is Rs.80,What is the
sum?

a) 11,880

b) 12,500

c) 13,250

d) 14,270

Sol:

Difference in simple and compound interest at the end of 2
years occurs because there is interest on first year interest. So Difference =
P×(R100)2

⇒ 80 = P×(8100)2

⇒ P=80×(1008)2 = 12,500

7. If the class marks in frequency distribution weights of
students be 128, 137, 146, 155, 164, 173 and 182 kgs then the first class
boundary is

a)121.5

b)122.5

c)123.5

d)124.5

Sol:

Rule for class boundary is = n1– (n2 – n1)/2.

So here n1 = 128, n2 = 137;

First class boundary = 128 – (137 – 128)/2 = 128 – 4.5 =
123.5

Hence option (C) is correct.

8. Consider a courier company A which can deliver 100
parcels in 5 days with 5 men working for 8 hours a day. Consider another
courier company B where every employee is equally efficient as that of company
B. Company B is short of one man when compared to A and has a policy of asking
its workers to work only for 6 hours a day. How long (in days) company B will
take to deliver 100 parcels.

a. 8.3

b. 24

c. 12

d. 6.6

Sol:

Total amount of work done by Members of A in delivering 100
parcels (in terms of man hours) = 5 × 5 × 8
= 200 hours

Company B has 4 employees and each of them work 6 hours a
day, Hence, work done per each day = 24

Therefore no.of days required to deliver 100 parcels =
Number of days required to do 200 units of work = 200/24 = 8.33. Hence answer
is a.

9. Consider two postmen A and B respectively. A is young and
can deliver 20 parcels in 3 hours while B is older than A and can deliver only
15 parcels in 4 hours. If the total number of parcels to deliver is 60, how
long they will take working together.

a. 121/12 hours

b. 144/36 hours

c. 144/25 hours

d. 121/25 hours

Sol:

Work done by 1st in 1
hour = 20/3 parcels / hour , Work done by 2nd om 1 hour = 15/4 parcels /
hour

Total work done by both together per hour = 20/3 + 15/4 = 125/12 parcels/hour

Time to do 60 unit work (ie, parcels)= 60 ÷ 125/12 = 60 ×
12/125 = 144/25 hours.

10. A clock strikes every hour once at 1.00 twice at 2.00
and so on. the clock takes 6 seconds to strike 5.00 and 12 seconds to strike
9.00 the time needed to strike 1.00 is negligible. how long does the clock need
for all its striking in 24 hours?

Sol:

The clock takes 12 secs to strike 9.00. So there are 8 gaps
between 9 strikings. So the gap between the striking is 12/8 = 1.5 seconds.

To strike 2.00 it takes = 1.5 seconds.

To strike 3.00 it takes = 3 seconds.

To strike 4.00 it takes = 4.5 seconds

................

................

To strike 12.00 it takes = 16.5 seconds.

So it takes a total of 1.5 + 3 + 4.5 + . . . . . . + 16.5 =
1.5 ( 1 + 2 + 3 + .... + 11) = 99 seconds to strike 12 hours.

For 24 hours it takes 99 × 2 = 198 seconds.

120. The first republic day of the India was celebrated on
26th January,1950. It was

A. Monday

B. Wednesday

C. Thursday

D. Friday

sol:

1-1-1 AD fall on Monday. We calculate the number of odd days
till 24th december, 1995.

Number of odd days till 1600 years = 0

1601 to 1700 = 5

1701 to 1800 = 5

1801 to 1900 = 5

49 years contains = 37 normal + 12 leap years =12 × 2 + 37 =
61 odd days = 61/7 = 5 odd days

25th January 1950 = 25/7 = 4 odd days

Total odd days =15 + 5 + 4 = 24/7 = 3 odd days

So 26th January,1950 is Thursday

12. On return from a business trip Mr. Chidambaram was to be
picked up from the railway station by

his coachman. Someone he managed a train connection earlier
and thus arrived two hours too early.

Immediately on arrived he rang up home for the coach and was
told that it had just left in order to be

exactly in time for the train by which he was scheduled to
come. To save the time he started walking

homeward at 3kmph. On the way he met the coachman who
brought him home an hour before

schedule. How far is the Mr. Chidambaram’s house from the
railway station?

a) 12 Km

b) 15 Km

c) 18 Km

d) 23 Km

Sol:

Very good questions. Appeared in Puzzles book of Ravi
Nirula.

Let the train's correct time is 9.00 am. Now chidambaram
reached the station at 7 am and he was informed that the coachman (car) left at
7 am. So car takes 2 hours to reach the station. This car expected to reach
home at 11 am.

But the car after picking up chidambaram, reached home 1
hour early. i.e., 10 am. So car has travelled 3 hours and 1.5 hours towards the
station. So it picked him up at 8.30 am. Car saved distance equivalent to 30
minutes. but this distance is covered by Chidambaram by walk. He took 1.5 hours
to cover this distance.

So Car speed is 3 times that of his walking speed. Car speed
= 3 × 3 = 9 km.

We know that car takes 2 hours to reach station. So the
distance = 9 × 2 = 18 km.

13. Its not easy having a mathematics professor as a friend.
When she invited you to her house she

says, “All the houses on my side of the street are numbered
consecutively in even numbers. There are

Six houses on my Side of my block and sum of their numbers
is 9870. You don’t know which block I

live on, and it’s a long street, but I will tell you that I
live in the lowest number on my side of the block. What’s the number? Or are you just going to
ring the first- numbered doorbell for twenty blocks?

a) 1580

b) 1640

c) 1650

d) 1680

Sol:

Given all the number are even consecutive numbers. This is
AP.

Formula for sum of numbers = Sn=n2[2a+(n−1)d]

Sum = 9870, n = 6, d = 2

9870=62[2a+(6−1)2]

⇒ 9870 = 3 (2a + 10)

⇒ 9840 = 6a

⇒ a = 1640

14. A watch which gains uniformly is 2 minutes low at noon
on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was
it correct?

A. 2 p.m. on Tuesday

B. 2 p.m. on Wednesday

C. 3 p.m. on Thursday

D. 1 p.m. on Friday

Sol:

2 minutes slow at monday noon.

4 min 48 sec fast at 2 pm next monday.

It ran faster than normal time by 6 min 48 secs = 408 sec in
7 days 2 hours = 170 hours.

It was correct when it advanced 120 seconds than normal
time.

The clock gains 408 seconds in 170 hours.

The clock gains 1 second in 170/408 hours

The clock gains 120 seconds in 170408×120 hours = 50 hours =
2 days 2 hours.

So the clock shows correct time on Wednesday 2 pm..

15. A clock is set at 5 a.m. The clock loses 16 minutes in
24 hours. What will be the true time when the clock indicates 10 p.m. on 4th
day?

A. 9 p.m

B. 10 p.m

C. 11 p.m

D. 12 p.m

sol:

Time from 5 a.m. on a day to 10 p.m. on 4th day = 89 hours.

The faulty clock shows only 1424 min for 24 hours in correct
clock.

So 1 minute of the faulty clock = 24/1424 hours

1 hour of the faulty clock = 24/1424 × 60 hours

89 hours of the faulty clock = 24/1424 × 60 × 89 = 90 hours.

So true time is 1 hour more than 10 pm. i.e., 11 pm.

16. On 8th march,2005,Wednesday falls. What day of the week was it on 8th
march,2004?

A. Monday

B. Tuesday

C. Wednesday

D. Friday

Sol:

Tuesday

17.Find the day of the week on 25th December,1995?

A. Monday

B. Wednesday

C. Friday

D. Sunday

Answer : A

Sol:

1-1-1 AD fall on Monday. We calculate the number of odd days
till 24th december, 1995.

Number of odd days till 1600 years = 0

1601 to 1700 = 5

1701 to 1800 = 5

1801 to 1900 = 5

1901 to 1994 = 94 + 23 = 117

3 + 0 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 24 = 50

So total odd days = 182 = 0 odd days.

So 25th december 1995 also falls on Monday.

18. Today is Thursday. The day after 59 days will be?

A. Sunday

B. Monday

C. Tuesday

D. Wednesday

Sol:

59/7 = 3 is remainder

Thursday + 3 days = Sunday

19. Today is Wednesday what will be the day after 94 days ?

A. Monday

B. Tuesday

C. Wednesday

D. Sunday

Sol:

94/7= 13 weeks and 3 days

Today is Wednesday, after three days if you count-it is
Saturday on 94th day

After 94th day, it is Sunday

1. At how many points
between 10 O'clock and 11 O'clock are the minute hand and hour hand of a clock
at an angle of 30 degrees to each other?

Sol:

Between 10 and 11, the minute hand and hour hand are at an
angle of 30o to each at (12/11) x 45
minutes past 10 = 49 1/11 minutes past 10. The next time they will be at angle
of 30o to each other will be at 11.

2. The egg vendor calls on his first customer & sells
half his eggs & half an egg. To the 2nd customer he sells half of what he
sells half of what he had left & half an egg. & to the 3rd customer he
sells half what he had then left & half an egg. By the way he did not break
any eggs. In the end three eggs were remaining . How many total eggs he was
having ?

Sol:

31 eggs.

After selling to 3 persons , he was left with 3 eggs.

After selling to 2 persons , he was left with 3 x 2 + 1 = 7
eggs.

After selling to 1 person , he was left with 7 x 2 + 1 = 15
eggs.

Before selling to 1 st person , he was having 15 x 2 + 1 =
31 eggs.

3. There are some people in party, 1/3rd left the party .
Then 2/5th of the remaining left the party , then 2/3rd of the remaining left
the party . At last 6 were remaining . How many people were in total ?

Sol:

45

If x persons were there in total , then

x × (1 – 1/3)× (1 – 2/5) ×(1 – 2/3) = 6

x×2/3 × 3/5 × 1/3 = 6

x = 6 × 5 × 3/2 = 45

4. Two trains are traveling from point A to point B such
that the speed of first train is 65 kmph and the speed of 2 train is 29 kmph.
Where is the distance b/w A and B such that the slower train reached 5 hrs late
compared to the faster?

Sol:

If x is the distance, then

x/29 – x/65 = 5

Then x = 5×29×6565−29 = 261.8055 kms

5. A person was fined for exceeding the speed limit by 10
km/hr.Another person was also fined for exceeding the same speed limit by twice
the same.If the second person was traveling at a speed of 35 km/hr,find the
speed limit.

a) 19 km/hr

b) 27 km/hr

c) 30 km/hr

d) 15 km/hr

Sol:

If x is speed limit,

Speed of first person = x + 10

Speed of 2nd person = x + 20

But speed of 2nd person = 35 kmph

x + 20 = 35

x = 15 kmph.

so speed limit is 15 kmph option D

6. The average of ten numbers is 7. If each number is
multiplied by 12 ,then the average of new set of numbers is :

a) 7

b) 19

c) 82

d) 84

Sol:

The avg will be = 12×7= 84

7. The average of eight numbers is 14. The average of six of
these numbers is 16.The average of the remaining two numbers is :

a) 4

b) 8

c) 16

d) none

Sol:

Average of eight numbers = 14

Average of six numbers = 16

Average will be = (14×8 – 16×6)/2

8. The average age of a class of 39 students is 15
years. If the age of the teacher be
included, then the average increases by 3 months .Find the age of the teacher.

a) 25 years

b) 27 years

c) 35 years

d) 28 years

Sol:

Sum of the ages of the students = 39×15 = 585

New average = 15 years 3 months = 15 + 14 year

Sum of the ages of students and teacher = 40×1514 = 40×614 =
610

Teacher age = 610 –
585 = 25 years.

9. Two trains start from stations A and B spaced 50 kms
apart at the same time and speed. As the trains start, a bird flies from one
train towards the other and on reaching the second train, it flies back to the
first train. This is repeated till the trains collide. If the speed of the
trains is 25 km/h and that of the bird is 100 km/h. How much did the bird
travel till the collision.

Sol:

Since the trains is travelling at 25 kmph, at each other,
the relative speed is 50 kmph.

Speed = 50 kmph

Distance = 50 km

Time to collision = distance / speed = 1 hr

Speed of bird = 100 kmph

Time flying = 1 hr (the bird is flying till the trains
collide)

Distance travelled = speed × time = 100 km

10. There are 20 poles with a constant distance between each
pole. A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole.

Sol:

Assuming the car starts at the first pole.

To reach the 12th pole, the car need to travel 11 poles (the
first pole doesn't count, as the car is already there).

11 poles 24 seconds

1 pole (24/11) seconds

To reach the last (20th) pole, the car needs to travel 19
poles.

19 pole 19 x (24/11) seconds

= 41.4545 seconds

11. Father's age is three years more than three times the
son's age. After three years, father's age will be ten years more than twice
the son's age. What is the father's present age?

Sol:

Let the son's present age be x years.then father's present
age will be 3x + 3 years.

After 3 years,3x + 3 + 3 = 2 (x + 3) + 10

Solving we get, x = 10.

Substituting x =10 in 3x + 3,

Hence father's present age will be x = 33 years.

12. In a railway station, there are two trains going. One in
the harbor line and one in the main line, each having a frequency of 10
minutes. The main line service starts at 5 o'clock and the harbor line starts
at 5.02 A.M. A man goes to the station every day to catch the first train that
comes. What is the probability of the man catching the first train?

Sol:

For each 10 min interval, if man comes in first 2 min, he'll
catch the 1st train, if he comes in next 8 min, he'll catch the 2nd train.

Hence for harbor line = (2/10) = 0.2 and for main line 0.8.

13. A ship went on a voyage. After it had traveled 180 miles
a plane started with 10 times the speed of the ship. Find the distance when they meet from
starting point.

Sol:

Let the speed of the ship = m miles/hr. and plane took 't'
hours to meet the ship

Then, m×t is the distance ship traveled after plane started

So we have, mt + 180 = 10mt

⇒ 9mt = 180

⇒ mt = 20

Hence distance = 180 + 20 = 200 miles

14. On 8th Feb, 2005 it was Tuesday. What was the day of the
week on 8th Feb, 2004?

a. Tuesday

b. Monday

c. Sunday

d. Wednesday

Sol:

Sunday

The year 2004 is a leap year and therefore, two days will be
preceded from Tuesday

15. At what time between 2 and 3 o'clock will the hands of a
clock be together?

a. 10×10/11

b. 10×11/10

c. 11×10/11

d. 12×10/11

Answer : d

Sol:

The hands of a clock would be together when the angle
between The hour hand and minute hand is Zero.
Now apply the formula: θ=∣∣∣30h−112m∣∣∣

Here θ = 0

⇒11/2m – 30h = 0

⇒11/2m – 30×2 = 0

⇒ m = 120/11

16. At what angle the hands of a clock are inclined at 15
minutes past 5?

a. 117/2 °

b. 64 °

c. 135/2 °

d. 145/2 °

Sol:

Apply the formula:

θ=∣∣∣30h−112m∣∣∣

⇒ Angle = 30 × 5 –11/2 × 15 = 150 – 165/2
= 135/2

17. At 3.40, the hour hand and the minute hand of a clock
form an angle of

a. 120°

b. 125°

c. 130°

d. 135°

Answer: C

Sol:

Use formula θ=∣∣∣30h−112m∣∣∣

Angle = 30×3 – 11/2 × 40 = 90 – 220 = 130°

18. How many times in a day, the hands of a clock are
straight?

a. 22

b. 24

c. 44

d. 48

Sol:

The hands of a clock point in opposite directions (in the
same straight line) 11 times in every 12 hours. (Because between 5 and 7 they
point in opposite directions at 6 o'clock only).

So, in a day, the hands point in the opposite directions 22
times.

19. Find the angle between the hour and the minute hand of a
clock when the time is 3.25.

a. 47 ½

b. 49 ½

c. 55 ½

d. 57 ½

Sol:

Formula : θ=∣∣∣30h−112m∣∣∣

Angle = 11/2 × 25 – 30×3 = 95/2 = 47.5

20. At what time, in minutes, between 3 o'clock and 4
o'clock, both the needles will coincide each other?

A. 5 1/11 °

B. 12 4/11 °

C. 13 4/11°

D. 16 4/11°

sol:

Formula : θ=∣∣∣30h−112m∣∣∣

Here angle is 0. So

11/2 m – 30 h = 0

11/2 m – 30 × 3 = 0

m = 180/11

= 16 4/11

Ans:: D

1. A starts business with Rs. 35,000 and after 5 months, B
joins with A as his partner. After a year, the profit is divided in the ratio
2:3. What is B’s contribution in the capital?

A) Rs .7500

B) Rs. 8000

C) Rs. 8500

D) Rs. 9000

Answer: D

Explanation:

Ratio in which profit is to be divided = 2 : 3

Assume that B's contribution to the capital = b

⇒ 3500 × 12 : b × 7 = 2 : 3

⇒ 3500 × 12/7 b = 2/3

⇒ b = (3500 × 12 × 3)/(2 × 7) = 500 × 6 ×
3 = 9000

2. Anand and Deepak started a business investing Rs. 22,500
and Rs.35,000 respectively. Out of a
total profit of Rs.13,800, Deepak’s share is _____

A) Rs.5,400

B) Rs.7,200

C) Rs.8,400

D) Rs.9,400

Answer: A

Explanation:

Ratio of their investments = 22500 : 35000 = 9 : 14

So Deepak' s share
= 923 × 13800 = Rs.5,400

3. Narasimha, Madhu and pavan started a business by
investing Rs.1,20,000, Rs.1,35,000 and Rs 1, 50,000 respectively. Find the share of Pavan, out of an annual
profit of Rs.56,700.

A) Rs.16,800

B) Rs.18,900

C) Rs.21,000

D) none

Answer: C

Explanation:

Ratio of their investments = 120000 : 135000 : 150000 = 8
: 9 : 10

Share of Pavan = 1027 × 56700 = 21,000

4. Out of four numbers ,the average of first three is 16 and
that of the last three is 15. If the
last number is 18,the first number is :

A) 20

B) 21

C) 23

D) 25

Answer: B

Explanation:

Let the numbers be a,b,c,d

Given, a + b + c = 48,
b + c + d = 45

Now, d = 18

thus, b + c + 18 = 45 ⇒ b + c = 27

Putting the value of b + c in a + b + c = 48

a + 27 = 48 ⇒ a = 21

5. A batsman makes a score of 87 runs in the 17th inning and
thus increases his average by 3 . Find his average after 17th inning.

A) 39

B) 38

C) 38.5

D) 39.5

Answer: A

Explanation:

Consider the avg for first 16 innings is x.

Then total runs scored till 16 innings is 16x.

Total runs after 17 innings = 16x + 87.

Thus, 16x+8717=x+3 ⇒ x = 36

So his average after 17 innings = 39.

6. Three years ago , the average age of A, B and C was 27
years and that of B and C 5 years ago was 20 years. A’s present age is :

A) 30 yrs

B) 35 yrs

C) 40 yrs

D) 48 yrs

Answer: C

Explanation:

Sum of the present ages of A, B and C = (27× 3 + 3 × 3)
years = 90 years.

Sum of the present ages of B and C = (20 × 2 + 5 × 2) years
= 50 years.

A's present age = 90 – 50 = 40 years.

7.The average of six numbers is 30. If the average of first four is 25 and that
of last three is 35, the fourth number is :

A) 25

B) 30

C) 35

D) 40

Answer: A

Explanation:

Let the six numbers be, a, b, c, d, e, f.

a + b + c + d + e + f = 30 × 6 = 180 - - - - (1)

a + b + c + d = 25 ×
4 = 100 - - - - (2)

d + e + f = 35 × 3 = 105 - - - - (3)

Add 2nd and 3rd equations and subtract 1st equation from
this.

d = 25

8. A and B are partners in a business. A contributes 1/4 of
the capital for 15 months and B received 2/3 of the profit . For how long B’s money was used.

A) 6 months

B) 9 months

C) 10 months

D) 1 year

Answer: C

Explanation:

B received 2/3 of the profit ⇒Their
profits ratio = A : B = 1 : 2

Let the total capital = 4 units

Then A's capital = 1

B's capital = 3

Assume B's money was used for b months

Then A : B = 1 × 15 : 3 × b = 1 : 2

⇒ 15 : 3b = 1 : 2

⇒ 153b=12

⇒ b = 10

9. At an election a
candidate who gets 84% of the votes is elected by a majority of 476 votes. What
is the total number of votes polled?

A) 672

B) 700

C) 749

D) 848

Answer: B

Explanation:

Let the total votes are 100x. Then winning candidate got
84x, and losing candidate got 16x.

⇒ 84x – 16 x = 476

⇒ 68 x = 476

⇒ x = 7

Total votes are 700.

10. A man buys a
cycle for Rs.1400 and sells it at loss of 15%.
What is the selling price of the cycle?

A) Rs.1090

B) Rs.1160

C) Rs.1202

D) Rs.1190

Answer: D

Explanation:

S.P = 85% of Rs.1400 ⇒ Rs.(85100 ×1400) = Rs.1190.

11. A shopkeeper purchased 70 kg of potatoes for Rs.420 and
sold the whole lot at the rate of Rs 6.50 per kg .What will be his gain
percent?

A) 4 1/6 %

B) 6 1/4 %

C) 8 1/3 %

D) 20%

Answer: C

Explanation:

Price per 1 kg = 42070 = Rs.6.

Profit per 1 kg = Rs.6.5 – Rs.6 = Rs.0.5

Profit for 70 kg = 0.5 × 70 = Rs.35

Gain % = 35420 × 100=
8.33% = 8 1/3

12. By selling 300
apples a seller gains the selling price of 60 apples. The gain percent of the
seller is

A) 200

B) 20%

C) 25%

D) 16 2/3%

Answer: C

Explanation:

We know that SP − CP = Profit

⇒300SP - 300CP = 60SP

⇒240SP = 300CP

⇒ SPCP=300240 = 54

Let SP = 5, and CP = 4

So profit percentage = 14×100=25%

13. The average monthly salary of 8 workers and one
supervisor in a factory was 430.Whenthesupervisor,whosesalarywas870 per month,
retired, a new person was appointed and then the average salary of 9 people was
$400 per month. The salary of the new supervisor is:

A. $700

B. $600

C. $430

D. $400

Answer: B

Explanation:

Total salary of 8 workers and supervisor together = 9 × 430
= 3870

Now total salary of 8 workers = 3870 − 870 = 3000

Total salary of 9 workers including the new supervisor = 9 ×
400 = 3600

Salary of the new supervisor = 3600 − 3000 = 600

14. The average of the first five prime numbers greater than
20 is:

A. 32.20

B. 31.00

C. 31.01

D. 32.00

Answer: A

Explanation:

Required prime numbers are 23, 29, 31, 37, 4.

Average will be (23 + 29 + 31 + 37 + 41)/5 = 32.20

15. The average score of 35 students in a class is 37. If
every student is given 3 grace marks, the new average of the class is:

A. 45

B. 34

C. 43

D. 40

E. None of these

Answer: D

Explanation:

Average score = 37

Grace mark 3 is given to 35 student then its average will be
3.

Hence new average = 37 + 3 = 40

16. The average age of a group of 10 students is 14 years.
If 5 more students join the group, the average age rises by 1 year. The average
age of the new students is:

A. 15 years

B. 17 years

C. 16 years

D. 18 years

E. None of these

Answer: D

Explanation:

Total age of the 10 students = 10 × 14 = 140

Total age of 15 students including the newly joined 5
students = 15 × 15 = 225

Total age of the new students = 225 − 140 = 85

Average age = 85/5 = 17 years

17. It rained as much as on Wednesday as on all the other
days of the week combined. If the average rainfall for the whole week was 3
cms, How much did it rain on Wednesday?

A. 3 cms

B. 10.5 cms

C. 15 cms

D. 2.62 cms

E. 4.5 cms

Answer: B

Explanation:

Let the rainfall on wednesday = 6x.

∴ Rainfall on the remaining days = 6x

Given,

(6x + 6x )/7 = 3

⇒12x = 21

⇒6x = 10.5

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